Technologies
Pattern Number #83
3569
569
69
9
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will iterate
based on the number of entry.
 |
| Pattern printing program |
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern83
{
public static void Main()
{
Console.WriteLine("Enter a random number: ");
string randNumber = Console.ReadLine();
int
j;
Console.WriteLine("-----Output-----");
Console.WriteLine();
if
(randNumber.Length == 0 || randNumber.Length == 1)
{
Console.Write(randNumber);
}
else
{
for (int i = 1; i <=
randNumber.Length; i++)
{
for (j = i; j <=
randNumber.Length; j++)
{
Console.Write(randNumber[j-1]);
}
Console.WriteLine();
}
}
Console.WriteLine();
Console.ReadKey();
}
}
}
Output:
The input
number here is 3569. So, the program will iterate according to the length of
the number. The output is shown below:
Enter a random number:
3569
-----Output-----
3569
569
69
9
Press any key to continue . . .
For any
query, comment us below.
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