Technologies
Pattern Number #81
1
A B
2 3 4
C D E F
5 6 7 8 9
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
 |
| Pattern printing program |
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern81
{
public static void Main()
{
Pattern81 obj = new Pattern81();
//Different solutions of creating the pattern.
/*(--Tip use the solution one at a time--)*/
//Solution1
obj.Solution1();
//Solution2
//obj.Solution2();
}
public void Solution1()
{
Console.WriteLine("Enter iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
j;
int
temp1 = 1;
int
temp2 = 1;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(int i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
if (i % 2 == 0)
{
Console.Write((char)(64 + temp1) + " ");
temp1++;
}
else
{
Console.Write(temp2 + " ");
temp2++;
}
}
Console.WriteLine();
}
Console.ReadKey();
}
public void Solution2()
{
Console.WriteLine("Enter iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
j;
char
ch = 'A';
int
temp = 1;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(int i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
if (i % 2 == 0)
{
Console.Write(ch + " ");
ch++;
}
else
{
Console.Write(temp + " ");
temp++;
}
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate 5 times. The output is shown
below:
Enter iteration times:
5
-----Output-----
1
A B
2 3 4
C D E F
5 6 7 8 9
Press any key to continue . . .
For any
query, comment us below.
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