Pattern Number #82
* ***** ***** *
** **** **** **
*** *** *** ***
**** ** ** ****
***** * * *****
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern82
{
public static void Main()
{
int
i, j, num, temp;
Console.WriteLine("Enter iteration times
: ");
num = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("-----Output-----");
Console.WriteLine();
temp = num;
for
(i = 1; i <= num; i++)
{
for (j = 1; j <= i; j++)
{
Console.Write("*");
}
Console.Write(" ");
for (j = temp; j >= 1; j--)
{
Console.Write("*");
}
Console.Write(" ");
for (j = temp; j >= 1; j--)
{
Console.Write("*");
}
Console.Write(" ");
for (j = 1; j <= i; j++)
{
Console.Write("*");
}
temp--;
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate 5 times. The output is shown below:
Enter iteration times :
5
-----Output-----
* ***** ***** *
** **** **** **
*** *** *** ***
**** ** ** ****
***** * * *****
Press any key to continue . . .
For any
query, comment us below.
Skip to
Main Table Pattern printing program
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