Pattern Number #96
A
1
BB
22
CCC
333
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern96
{
public static void Main()
{
Console.WriteLine("Enter loop iteration times: ");
int
num = Convert.ToInt32(Console.ReadLine());
int
j;
int
i;
int
n;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(i = 1; i <= num; i++)
{
for (n = 1; n <= 2; n++)
{
if (n % 2 == 0)
{
for (j = 1; j <= i; j++)
{
Console.Write(i);
}
}
else
{
for (j = 1; j <= i; j++)
{
Console.Write((char)(64 + i));
}
}
Console.WriteLine();
}
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 3. So, the program will iterate three times. The output is shown
below:
Enter loop iteration times:
3
-----Output-----
A
1
BB
22
CCC
333
Press any key to continue . . .
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query, comment us below.
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