Technologies
Pattern Number #99
-----1
----212
---32123
--4321234
-543212345
--4321234
---32123
----212
-----1
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
 |
| Pattern printing program |
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern99
{
public static void Main()
{
Console.WriteLine("Enter loop iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
j;
int
i;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(i = 1; i <= n; i++)
{
for (j = n; j >= i; j--)
{
Console.Write("-");
}
for (j = i; j >= 1; j--)
{
Console.Write(j);
}
for (j = j + 2; j <= i; j++)
{
Console.Write(j);
}
Console.WriteLine();
}
for
(i = n - 1; i >= 1; i--)
{
for (j = n; j >= i; j--)
{
Console.Write("-");
}
for (j = i; j >= 1; j--)
{
Console.Write(j);
}
for (j = j + 2; j <= i; j++)
{
Console.Write(j);
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate five times. The output is shown
below:
Enter loop iteration times:
5
-----Output-----
-----1
----212
---32123
--4321234
-543212345
--4321234
---32123
----212
-----1
Press any key to continue . . .
For any
query, comment us below.
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