SSC CGL 2017 TIER 2 RESULT OUT

SSC CGL 2017 TIER 2 result out with the unexpected cut-off marks. This times SSC indicates that now the competition is very tough.

Click here to check your marks 

Steps to check your marks: -

1)    Click on the above link.

2)    Click on the write-up => ("Click here") to see cut off of tier 2 exam

3)    Click on the result => to see the result of tier 2 exam.

4) Download the PDF for future usage.

All the best for your result. Comment your views and discuss what will be the expected cut-off of SSC-CGL 2016 Tier-1. 

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REPCO BANK LTD. Recruitment for Assistant Manager and Assistant General Manager 2017

REPCO BANK LTD. Recruitment for Assistant Manager (Scale-I)and Assistant General Manager(Scale III) 2017

Date of Posting: 27/02/2017

Company Name and Type: REPCO BANK LTD

Last date of submission: 10-03-2017.

Hiring Process: Candidates will be selected by

1. Written exam

2. Personal Interview

No. of Vacancy:

1. Assistant Manager Legal (Scale I) - 2

2. Assistant General Manager Legal (Scale III) - 1

Qualification:

1. Assistant Manager Legal (Scale I) - Applicant must Pass with minimum 60% in aggregate in BL/LLB from a recognized university.

2. General Manager Legal (Scale III) – Applicant Graduate in Law from a recognized university and a member of Bar council of the state concerned.

Age Limit: 

1. Minimum 24 – Maximum 30 years as on 30-06-2016 for Scale I

2. Minimum 30 – Maximum 40 years as on 30-06-2016 for Scale III

Annual CTC: 

1. Assistant Manager Legal (Scale I) – 9.15 CTC

2. Assistant General Manager Legal (Scale III) – 13.85 CTC

Application Fees: For all Candidate, there is a (Non-refundable) fee of Rs. 700. The fee is to be paid by either Bank Pay order or Demand Draft issued by a commercial bank.

How to Apply: All the interested Candidates can post their Bio- Data in English, before the last date of submission.

Website: www.repcobank.com

Notification: To read full notification/Information Click Here

Important Dates- 

Last date for Submission as per notification:  10/03/2017

''Note: There is a service bond of 2 years"

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Formula based program

Formula #3 (Perimeter and area of semi-circle)

Enter radius: 5

Perimeter of semi-circle: 15.707963267949

Area of semi-circle: 39.2699081698724

The program for the formula is written in C# programming language and will accept a number as radius. Based on the formula it will find out the perimeter and area of semi-circle.

 

Formula based program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these formula.

Practical Implementation:

using System;

namespace patternProblem.Formula

{

    class Formula3     //area and perimeter of semi-circle

    {

        static void Main(string[] args)

        {

            Console.Write("Enter radius: ");

            double radius = Convert.ToDouble(Console.ReadLine());

            double area = 0.0, perimeter = 0.0;

            perimeter = Math.PI * radius;

            area = (Math.PI * (Math.Pow(radius, 2)) / 2);

            Console.WriteLine("Perimeter of semi-circle: {0}", perimeter);

            Console.WriteLine("Area of semi-circle: {0}", area);

            Console.ReadKey();

        }

    }

}

Output:

The input radius here is 7. So, based on the semi-circle formula. The output is shown below:

Enter radius: 7

Perimeter of semi-circle: 21.9911485751286

Area of semi-circle: 76.9690200129499

Press any key to continue . . .

For any query, comment us below.

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Formula based program

Formula #2 (Perimeter and area of circle)

Enter radius: 5

Perimeter of circle: 31.4159265358979

Area of circle: 78.5398163397448

The program for the formula is written in C# programming language and will accept a number as radius. Based on the formula it will find out the perimeter and area of circle.

 

Formula based program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these formula.

Practical Implementation:

using System;

namespace patternProblem.Formula

{

    class Formula2     //area and perimeter of circle

    {

        static void Main(string[] args)

        {

            Console.Write("Enter radius: ");

            double radius = Convert.ToDouble(Console.ReadLine());

            double area = 0.0, perimeter=0.0;

            perimeter = 2* Math.PI * radius;

            area = Math.PI * (Math.Pow(radius, 2));

            Console.WriteLine("Perimeter of circle: {0}", perimeter);

            Console.WriteLine("Area of circle: {0}", area);

            Console.ReadKey();

        }

    }

}

Output:

The input radius here is 7. So, based on the circle formula. The output is shown below:

Enter radius: 7

Perimeter of circle: 43.9822971502571

Area of circle: 153.9380400259

Press any key to continue . . .

For any query, comment us below.

Skip to Main Table – Formula based program

Previous – Formula based program #1

Next – Formula based program #3

Click imagination hunt to read latest blogs.

Posted By - +Manish Kumar Gautam +LIVE VIAR +ASP.NET SOLUTIONS

Keep learning and sharing...

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Formula based program

Formula #1 (Leap year)

Enter a year: 2016

Year is a leap year

The program for the formula is written in C# programming language and will accept a number as input year. Based on the conditions it will check whether the year is a leap year or not.

 

Formula based program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code these formula.

Practical Implementation:

using System;

namespace patternProblem.Formula

{

    class Formula1     //Leap year

    {

        static void Main(string[] args)

        {

            Console.Write("Enter a year: ");

            int year = Convert.ToInt32(Console.ReadLine());

            if (((year % 100 != 0) && (year % 4 == 0)) || (year % 400 == 0))

            {

                Console.WriteLine("Year is a leap year");

            }

            else

            {

                Console.WriteLine("Year is not a leap year");

            }

            Console.ReadKey();

        }

    }

}

Output:

The input year here is 2016. So, based on the conditions it will check whether the year is a leap year or not. The output is shown below:

Enter a year: 2016

Year is a leap year

Press any key to continue . . .

For any query, comment us below.

Skip to Main Table – Formula based program

Next – Formula based program #2

Click imagination hunt to read latest blogs.

Posted By - +Manish Kumar Gautam +LIVE VIAR +ASP.NET SOLUTIONS

Keep learning and sharing...

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