Pattern Number #117
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern117
{
public static void Main()
{
Console.WriteLine("Enter iteration times: ");
int
rows = Convert.ToInt32(Console.ReadLine());
int
coef = 1, space, i, j;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(i = 0; i < rows; i++)
{
for (space = 1; space <= rows - i; space++)
{
Console.Write(" ");
}
for (j = 0; j <= i; j++)
{
if (j == 0 || i == 0)
{
coef = 1;
}
else
{
coef = coef * (i - j +
1) / j;
}
Console.Write(" " + coef);
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate five times. The output is shown
below:
Enter iteration times:
5
-----Output-----
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
Press any key to continue . . .
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query, comment us below.
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Main Table Pattern printing program
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