Pattern Number #116
*
*A*
*A*A*
*A*A*A*
*A*A*A*A*
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern116
{
public static void Main()
{
Console.WriteLine("Enter iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
j;
int
num;
int
count = 1;
num = n;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(int i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
Console.Write("*");
if (i > 1 && count
< i)
{
Console.Write((char)(65));
count++;
}
}
num--;
count = 1;
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate five times. The output is shown
below:
Enter iteration times:
5
-----Output-----
*
*A*
*A*A*
*A*A*A*
*A*A*A*A*
Press any key to continue . . .
For any
query, comment us below.
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