Technologies
Pattern Number #90
# # # # # * # # # # #
# # # # * # * # # # #
# # # * # # # * # # #
# # * # # # # # * # #
# * # # # # # # # * #
* # # # # # # # # # *
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
 |
| Pattern printing program |
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern90
{
public static void Main()
{
int
i, j, num, temp;
Console.WriteLine("Enter iteration times : ");
num = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("-----Output-----");
Console.WriteLine();
temp = num;
for
(i = 1; i <= (num + 1); i++, temp--)
{
for (j = 1; j <= temp; j++)
{
Console.Write(" #");
}
for (j = 1; j <= i; j++)
{
if (j == 1)
{
Console.Write(" *");
}
else
{
Console.Write(" #");
}
}
for (j = i; j > 1; j--)
{
if (j == 2)
{
Console.Write(" *");
}
else
{
Console.Write(" #");
}
}
for (j = temp; j >= 1; j--)
{
Console.Write(" #");
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate 5 times. The output is shown
below:
Enter iteration times :
5
-----Output-----
# # # # # *
# # # # #
# # # # * #
* # # # #
# # # * # #
# * # # #
# # * # # #
# # * # #
# * # # # #
# # # * #
* # # # # #
# # # # *
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