Pattern Number #2
1
1 2
1 2 3
1 2 3 4
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Note:
Read articles on how to use Loops
and Conditions.
Let’s find out a simple and easy way to
code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern2
{
public static void Main(string[] args)
{
int
i = 0, j = 0;
Console.WriteLine("Number of iteration: ");
int
n = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
Console.Write(j + " ");
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 4. So, the program will iterate four times. The output is shown
below:
Number of iteration:
4
-----Output-----
1
1 2
1 2 3
1 2 3 4
Press any
key to continue . . .
For any
query, comment us below.
Skip to Main
Table Pattern printing program
Keep learning and sharing...
No comments:
Post a Comment