Pattern Number #17
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern17
{
public static void Main()
{
Console.WriteLine("Enter iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(int i = n; i >= 1; i--)
{
for (int j = 1; j <= i; j++)
{
Console.Write(j + " ");
if (j == i)
{
for (int k = (j - 1); k >= 1; k--)
{
Console.Write(k + " ");
}
}
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input number
here is 5. So, the program will iterate five times. The output is shown below:
Enter iteration times:
5
-----Output-----
1 2 3 4 5 4 3 2 1
1 2 3 4 3 2 1
1 2 3 2 1
1 2 1
1
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to continue . . .
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query, comment us below.
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Main Table Pattern printing program
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