Simple program

Simple program #2 (Check whether a number is even or odd using ternary or conditional operator)

Number: 5, is Odd.

Number: 10, is Even.

The program is written in C# programming language and will accept a number as input. The logic of the program is to find whether the number is even or odd using ternary or conditional operator.

 

Simple program

Note: If you are new to C# and Console Application. Try to code First C# Program

Note: Read articles on how to use Loops and Conditions.

Let’s find out a simple and easy way to code the program.

Practical Implementation:

using System;

namespace patternProblem.Simple_program

{

    class Simple2   //Checking Even and Odd number using ternary or conditional operator

    {

        static void Main(string[] args)

        {

            Console.Write("Enter number: ");

            int n = Convert.ToInt32(Console.ReadLine());

            string output = string.Empty;

           

            output = (n % 2 == 0) ? "Number: {0}, is Even." : "Number: {0}, is Odd.";

            Console.WriteLine(output, n);

            Console.ReadKey();

        }

    }

}

Output:

The input number here is 5, which is odd. The output is shown below:

Enter number: 5

Number: 5, is Odd.

Press any key to continue . . .

For any query, comment us below.

Skip to Main Table Simple program

Previous - Simple program #1

Next – Simple program #3

Click imagination hunt to read latest blogs.

Posted By - +Manish Kumar Gautam +LIVE VIAR +ASP.NET SOLUTIONS 

Keep learning and sharing...