Technologies
Pattern Number #66
ABCBA
AB BA
A A
AB BA
ABCBA
 |
| Pattern printing program |
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern66
{
public static void Main()
{
Console.WriteLine("Enter loop iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
num = n;
int
j;
int
i;
int
k;
string space = "";
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(i = 1; i <= n; i++, num--)
{
for (j = 1; j <= ((n + 1) - i); j++)
{
if (j >= n)
{
break;
}
else
{
Console.Write((char)(64 + j));
}
}
for (k = 1; k < i; k++)
{
if (k <= i)
{
Console.Write(space.PadRight(k));
}
else
{
Console.Write(space.PadRight(k -
1));
}
}
for (j = num; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
Console.WriteLine();
}
for
(i = 2; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
if (j == n)
{
break;
}
Console.Write((char)(64 + j));
}
for (k = 1; k <= n - i; k++)
{
Console.Write(space.PadRight(k));
}
for (j = i; j >= 1; j--)
{
Console.Write((char)(64 + j));
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 3. So, the program will iterate three times. The output is shown
below:
Enter loop iteration times:
3
-----Output-----
ABCBA
AB BA
A A
AB BA
ABCBA
Press any key to continue . . .
For any
query, comment us below.
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