Pattern Number #53
4444444
4333334
4322234
4321234
4322234
4333334
4444444
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern53
{
public static void Main()
{
Console.WriteLine("Enter loop iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
j;
int
i;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(i = 0; i < 2 * n - 1; i++)
{
for (j = 0; j < 2 * n - 1; j++)
{
Console.Write(1 + Math.Max(Math.Abs(n - j - 1), Math.Abs(n - i - 1)));
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 4. So, the program will iterate four times. The output is shown
below:
Enter loop iteration times:
4
-----Output-----
4444444
4333334
4322234
4321234
4322234
4333334
4444444
Press any key to continue . . .
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query, comment us below.
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