Pattern Number #23
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5
4 4 4 4
3 3 3
2 2
1
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern23
{
public static void Main()
{
Console.WriteLine("Enter iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
j;
int
i;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
Console.Write(i + " ");
}
Console.WriteLine();
}
if
(i == (n + 1))
{
for (i = i - 2; i >= 1; i--)
{
for (j = 1; j <= i; j++)
{
Console.Write(i + " ");
}
Console.WriteLine();
}
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate five times. The output is shown
below:
Enter iteration times:
5
-----Output-----
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5
4 4 4 4
3 3 3
2 2
1
Press any
key to continue . . .
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query, comment us below.
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Main Table Pattern printing program
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