Pattern Number #22
A B C D E D C B A
B C D E D C B
C D E D C
D E D
E
The program for the pattern is written
in C# programming language and will accept a number as input. The loops will
iterate based on the number of entry.
Let’s find out a simple and easy way
to code these pattern.
Practical Implementation:
using System;
namespace patternProblem
{
class Pattern22
{
public static void Main()
{
Console.WriteLine("Enter iteration times: ");
int
n = Convert.ToInt32(Console.ReadLine());
int
j;
Console.WriteLine("-----Output-----");
Console.WriteLine();
for
(int i = 1; i <= n; i++)
{
for (j = i; j > 1; j--)
{
Console.Write(" ");
}
for (j = i; j <= n; j++)
{
Console.Write((char)(j + 64) + " ");
}
for (j = j - 2; j >= i; j--)
{
Console.Write((char)(j + 64) + " ");
}
Console.WriteLine();
}
Console.ReadKey();
}
}
}
Output:
The input
number here is 5. So, the program will iterate five times. The output is shown
below:
Enter iteration times:
5
-----Output-----
A B C D E D C B A
B C D E D C
B
C D E D C
D E D
E
Press any
key to continue . . .
For any
query, comment us below.
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